📐 Stress Tensor P
P₁₁ Normal
P₁₂ Shear
P₁₃ Shear
P₂₁ Shear
P₂₂ Normal
P₂₃ Shear
P₃₁ Shear
P₃₂ Shear
P₃₃ Normal
Shear Stress (Off‑Diagonal)
Normal vector n = (1.00, 0.00, 0.00)
Total stress Pₙ = (0.00, 0.00, 0.00)
Normal component 0.00
Shear component 0.00
💡 Initially n=(1,0,0), Pₙ coincides with P₁. Verify normal = P₁₁, shear = √(P₁₂²+P₁₃²).